Truncated cuboctahedron

Truncated cuboctahedron
Truncated cuboctahedron
Truncated cuboctahedron
(Click here for rotating model)
Type Archimedean solid
Uniform polyhedron
Elements F = 26, E = 72, V = 48 (χ = 2)
Faces by sides 12{4}+8{6}+6{8}
Schläfli symbol t0,1,2{4,3}
Wythoff symbol 2 3 4 |
Coxeter-Dynkin CDel node 1.pngCDel 4.pngCDel node 1.pngCDel 3.pngCDel node 1.png
Symmetry Oh, [4,3], (*432)
Dihedral Angle
References U11, C23, W15
Properties Semiregular convex zonohedron
Truncated cuboctahedron color
Colored faces
Truncated cuboctahedron
4.6.8
(Vertex figure)
Disdyakisdodecahedron.jpg
Disdyakis dodecahedron
(dual polyhedron)
Truncated cuboctahedron Net
Net

In geometry, the truncated cuboctahedron is an Archimedean solid. It has 12 square faces, 8 regular hexagonal faces, 6 regular octagonal faces, 48 vertices and 72 edges. Since each of its faces has point symmetry (equivalently, 180° rotational symmetry), the truncated cuboctahedron is a zonohedron.

Contents

Cartesian coordinates

Orthographic projections
3-cube t012.svg 3-cube t012 B2.svg

The Cartesian coordinates for the vertices of a truncated cuboctahedron having edge length 2 and centered at the origin are all permutations of:

(±1, ±(1+√2), ±(1+2√2))

Area and volume

The area A and the volume V of the truncated cuboctahedron of edge length a are:

A = 12(2+\sqrt{2}+\sqrt{3}) a^2 \approx 61.7551724a^2
V = (22+14\sqrt{2}) a^3 \approx 41.7989899a^3.

Vertices

To derive the number of vertices, we note that each vertex is the meeting point of a square, hexagon, and octagon.

  • Each of the 12 squares with their 4 vertices contribute 48 vertices because 12 \times 4=48.
  • Each of the 8 hexagons with their 6 vertices contribute 48 vertices because 8 \times 6=48.
  • Each of the 6 octagons with their 8 vertices contribute 48 vertices because 6 \times 8=48.

Therefore, there may seem to exist 48 + 48 + 48 = 144 vertices. However, we have over-counted the vertices thrice since a square, hexagon, and octagon meet at each vertex. Consequently, we divide 144 by 3 to correct for our over-counting: 144 / 3 = 48.

Dual

If the original truncated cuboctahedron has edge length 1, its dual disdyakis dodecahedron has edge lengths \frac{2}{7}\sqrt{30-3\sqrt{2}}, \frac{3}{7}\sqrt{6(2+\sqrt{2})} and \frac{2}{7}\sqrt{6(10+\sqrt{2})}.

Uniform colorings

There is only one uniform coloring of the faces of this polyhedron, one color for each face type.

A 2-uniform coloring also exists with alternately colored hexagons.

Other names

Alternate interchangeable names are:

The name truncated cuboctahedron, given originally by Johannes Kepler, is a little misleading. If you truncate a cuboctahedron by cutting the corners off, you do not get this uniform figure: some of the faces will be rectangles. However, the resulting figure is topologically equivalent to a truncated cuboctahedron and can always be deformed until the faces are regular.

The alternative name great rhombicuboctahedron refers to the fact that the 12 square faces lie in the same planes as the 12 faces of the rhombic dodecahedron which is dual to the cuboctahedron. Compare to small rhombicuboctahedron.

One unfortunate point of confusion: There is a nonconvex uniform polyhedron by the same name. See nonconvex great rhombicuboctahedron.

See also

Notes

  1. ^ Wenninger, Magnus (1974), Polyhedron Models, Cambridge University Press, ISBN 978-0-521-09859-5, MR0467493  (Model 15, p. 29)
  2. ^ Williams, Robert (1979). The Geometrical Foundation of Natural Structure: A Source Book of Design. Dover Publications, Inc. ISBN 0-486-23729-X.  (Section 3-9, p. 82)
  3. ^ Cromwell, P.; Polyhedra, CUP hbk (1997), pbk. (1999). (p. 82)

External links


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